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Sketch The Graph Of Yxx2 9
Y x2 9x2 92. If you realize this is a circle with radius so sketch that on 3d plane.
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Y x2 9 2x2x2 92.
Sketch the graph of yxx2 9. Look again you have to graph in 3d plane. Notice if we graph the final equation we get. Notice if we graph the original equation we get.
Use the form to find the values of and. Make z9 x2 9y2 and then make x and y positive. Critical numbers will occur whenever the derivative equals 0 or the derivative is undefined.
So instead this would be an elliptic paraboloid. Tap for more steps. Find the properties of the given parabola.
Complete the square for. You can put this solution on your website. Find the x and y intercepts of each graph yx2 9.
So if these two equations were graphed on the same coordinate plane one would overlap another perfectly. Tap for more steps. Then set z0 and youll have x29y2 1.
Notice how the vertex is also. Consider the vertex form of a parabola. The derivative is undefined at x 3 but this is undefined in the actual function as well so these are actually not critical numbers.
Found 2 solutions by fombitz ewatrrr. Answer by fombitz32352 show source. So the x coordinate of the vertex is x 0.
Tap for more steps. To find the x intercept set and solve for. Rewrite the equation in vertex form.
So when x b2a x 02 0. When x 0 y 0 9 9 but we already knew that so the coordinates of the vertex are 0 9 and that points already plotted. So this visually verifies our answer.
So the equation would be x29y2 9 z. Now just draw a super smooth curve through the plotted points and youve got the graph. Seamus o 9 years ago.
To find the y intercept set and solve for. Notice how the vertex is.
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